Na+ has completely filled K and L shells. Explain.
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Answered by
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since atomic no.of sodium is 11 then it's electronic configuration will be (2,8,1) so it's k and l shells are completely filled
Answered by
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Na has atomic number 11
So it's electronic configuration is 2,8,1
So Na looses this 1 electron to form octet or rather to form Na+ ion
Thus Na+ion has 2 electrons in K shell and 8 in L shell
Now we know that maximum no of electrons in a shell can be found by the formula 2n^2
Thus maximum number of electrons in K shell is 2×1^2=2 and that in L shell is 2×2^2=2×4=8
Thus we see that Na+ ion has completely filled K and L shells
HOPE IT HELPS YOU
So it's electronic configuration is 2,8,1
So Na looses this 1 electron to form octet or rather to form Na+ ion
Thus Na+ion has 2 electrons in K shell and 8 in L shell
Now we know that maximum no of electrons in a shell can be found by the formula 2n^2
Thus maximum number of electrons in K shell is 2×1^2=2 and that in L shell is 2×2^2=2×4=8
Thus we see that Na+ ion has completely filled K and L shells
HOPE IT HELPS YOU
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