Question

निम्न में से क्या द्विघात समीकरण है?
(a) x2
-79= x2
+9x+1 (b) 12x2
-7=0
(c) 3x2
+11x+14=x(3x+5x) (d) -x2
+11x-18=0

Answer 1

$a) Given \: equation : x^{2} - 79 = x^{2}+9x+1$

/* subtract bothsides of the equation by x², we get */

$\implies x^{2} - 79 - x^{2} = x^{2}+9x+1 - x^{2}$

$\implies -79 = 9x + 1$

$\blue { ( Degree \: of \: the\: equation \:is \: 1 )}$

$So, it \:is \:a \: Linear \: equation$

$b) Given \: 12x^{2} - 7 = 0$

$\blue { ( Degree \: of \: the\: equation \:is \: 2 )}$

$\green {So, it \:is \:a \: Quadratic\: equation.}$

$c) Given \: equation : 3x^{2}+11x+14=x(3x+5x)$

$\implies 3x^{2}+11x+14= x\times 8x$

$\implies 3x^{2}+10x+14= 8x^{2}$

$\implies 3x^{2}+10x+14-8x^{2}=0$

$\implies -5x^{2}+10x+14=0$

$\blue { ( Degree \: of \: the\: equation \:is \: 2 )}$

$\green {So, it \:is \:a \: Quadratic\: equation.}$

$d) Given \: equation : -x^{2}+11x-18 = 0$

$\blue { ( Degree \: of \: the\: equation \:is \: 2 )}$

$\green {So, it \:is \:a \: Quadratic\: equation.}$

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Answer 2

Answer:

a)Givenequation:x2−79=x2+9x+1

/* subtract bothsides of the equation by x², we get */

\implies x^{2} - 79 - x^{2} = x^{2}+9x+1 - x^{2}⟹x2−79−x2=x2+9x+1−x2

\implies -79 = 9x + 1⟹−79=9x+1

\blue { ( Degree \: of \: the\: equation \:is \: 1 )}(Degreeoftheequationis1)

So, it \:is \:a \: Linear \: equationSo,itisaLinearequation

b) Given \: 12x^{2} - 7 = 0b)Given12x2−7=0

\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)

\green {So, it \:is \:a \: Quadratic\: equation.}So,itisaQuadraticequation.

c) Given \: equation : 3x^{2}+11x+14=x(3x+5x)c)Givenequation:3x2+11x+14=x(3x+5x)

\implies 3x^{2}+11x+14= x\times 8x⟹3x2+11x+14=x×8x

\implies 3x^{2}+10x+14= 8x^{2}⟹3x2+10x+14=8x2

\implies 3x^{2}+10x+14-8x^{2}=0⟹3x2+10x+14−8x2=0

\implies -5x^{2}+10x+14=0⟹−5x2+10x+14=0

\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)

\green {So, it \:is \:a \: Quadratic\: equation.}So,itisaQuadraticequation.

d) Given \: equation : -x^{2}+11x-18 = 0d)Givenequation:−x2+11x−18=0

\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)

\green {So, it \:is \:a \: Quadratic\: equation.}So,itisaQuadraticequation.

•••♪

Step-by-step explanation:

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