Question

निम्नलिखित के मान सर्वसमिका (a+b)3=a3+b3+3ab(a+b)​

Answer 1

Answer:

Hence proved in the explanation.

Step-by-step explanation:

(a+b)³=a³+b³+3ab(a+b)

LHS

(a+b)(a+b)(a+b)

= (a²+b²+2ab)(a+b)

= a²(a+b)+b²(a+b)+2ab(a+b)

= a³+a²b+b²a+ b³+2a²b +2ab²

= a³+ 3ab²+3a²b+ b³

= a³+b³+3ab(a+b)

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