Question

11. Perimeter of a rectangle is 40 cm. The length of the rectangle is 3 times its breadth. Find the length and breadth of the rectangle.​

Answer 1

Length and Breadth of the Rectangle is 15 cm and 5 cm Respectively.

Given

• Perimeter of a rectangle - 40 cm
• Length = 3 times of Breadth

Explanation:

Let the Breadth of the Rectangle be x

again,

Length of the Rectangle be 3x

FORMULA

$\\ \circ {\boxed{\underline{\sf{ Perimeter_{(Rectangle)} = \purple{2(l+b)} }}}}$

Now, We can use this formula to find the required values as:

$\colon\implies{\sf{ 40 = 2(3x+x) }} \\ \\ \\ \colon\implies{\sf{ 40 = 2(4x) }} \\ \\ \\ \colon\implies{\sf{ \cancel{40} = \cancel{8} \ x }} \\ \\ \\ \colon\implies{\boxed{\mathfrak\red{ x = 5 }}}$

After substituting values,

$\colon{\boxed{\boxed{\sf\green{ Breadth = x = 5 \ cm }}}}$

$\colon{\boxed{\boxed{\sf\orange{ Length = 3x = 15 \ cm }}}}$

Hence,

• Length and Breadth of the Rectangle is 15cm and 5cm Respectively.

Answer 2

Question :-

Perimeter of a rectangle is 40 cm. The length of the rectangle is 3 times its breadth. Find the length and breadth of the rectangle.

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Solution :-

Let the Length and Breadth of the Rectangle be 15 cm and 5 cm respectively.

Given Information :-

Perimeter of a rectangle = 40 cm

Length = 3 times of Breadth

To Find :-

Length and Breadth of the Rectangle.

Calculation :-

Let the Breadth of the Rectangle be 'x'

again,

Length of the Rectangle be '3x'

Formula Used :-

$\\ {\boxed{\underline{\sf{ Perimeter\:of\:Rectangle)} = {2(l+b)} }}}}$

Then,

$\colon\implies{\sf{ 40 = 2(3x+x) }} \\ \\ \\ \colon\implies{\sf{ 40 = 2(4x) }} \\ \\ \\ \colon\implies{\sf{ \cancel{40} = \cancel{8} \ x }} \\ \\ \\ \colon\implies{\boxed{\sf{ x = 5 }}}$

Putting the values,

${\boxed{\boxed{\sf{ Breadth = x = 5 \ cm }}}}$

${\boxed{\boxed{\sf{ Length = 3x = 15 \ cm }}}}$

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Final Answer :-

Length and Breadth of the Rectangle is 15 cm and 5 cm respectively.

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