Question

Na2S2O3 react with Iodine calculate oxidation number

Answer 1

Answer:

written below-

Explanation:

Na2S2O3 + I2 ---> Na2S4O6 + 2Nal

....is the balanced chemical equation.

The oxidation state of Sulphur in Na2S2O3( also called hypo) is +2

Also, the oxidation state of Sulphur in Na2S4O6 is +2.5

The change in oxidation state per 1 S atom is 0.5

Thus the change in oxidation state per 2 Sulphur atoms is 2x0.5= 1

Hence the n-factor of hypo(Na2S2O3) in Iodometry is 1.

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