Question

namarata bought two dress for rupess 1200. She sold one of them at a profit of 8% and the other at a loss of 6%. If the selling price if both them is same. Find the cost price of each dress​

Answer 1

Let the cost price of first dress be 'x'

Let the cost price of second dress be '1200 - x'

Profit on first dress = 8 %

Loss on second dress = 6 %

According to question, selling price of both dresses is same, so we get that

$\frac{100 + 8}{100} \times x = \frac{100 - 6}{100} \times (1200 - x)$

$\frac{108}{100}x = \frac{94}{100}(1200 - x)$

$1.08x = 0.94(1200 - x)$

$1.08x = 1128 - 0.94x$

$1.08x + 0.94x = 1128$

$2.02x = 1128$

$x = \frac{1128}{2.02}$

$x = 558.42$

Hence, cost price of first dress is Rs. 558.42 and the cost price of second dress is Rs. 1200 - Rs. 558.42 = Rs. 641.58