Question

Name of fourth and fifth member of homologous series of acetic acid

Answer 1

So, if we put n = 4 in the general formula CnH2n +1OH then the molecular formula of the fourth member of the homologous series will become C4H2 * 4 + 1OH or C4H9OH.

So, if we put n = 5 in the general formula CnH2n + 1OH, then the molecular formula of the fifth member of the alcohol series will become C5H2 * 5 + 1OH or C5H11OH.So, if we put n = 5 in the general formula CnH2n + 1OH, then the molecular formula of the fifth member of the alcohol series will become C5H2 * 5 + 1OH or C5H11OH.