Name the following H3C–CH = CH–CH3
HC ≡ C–CH3
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H3C–CH = CH–CH3--HC ≡ C–CH3
Hept-5-en-2-yne
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As there is 7 carbons the common name is hept.
as triple bond comes on 2nd carbon from the left we should take the serials from left to right,
there is also a double bond on 5th carbon.
therefore the name is
Hept 5 ene 2 yne
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