Social Sciences, asked by Pandeyji361, 11 months ago

Name the gas evolved in end of the following cases
(i) Action of heat on solid iodine.
(ii) Action of very dilute nitric acid on manganese
(iii) Action of concentrated sulphuric acid on zinc
(iv) Addition of hydrochloric acid to potassium permanganate
(v) Sulphur reacts with nitric acid.

Answers

Answered by Sravan5380
1

Answer:

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Answered by topwriters
2

(i) Iodine

(ii) Hydrogen

(iii) Hydrogen

(iv) Chlorine

(v) Nitrogen dioxide

Explanation:

(i) Iodine - When Iodine crystals are heated, the element sublimes and form a purple colored dense vapor.

(ii) Hydrogen - Manganese reacts with very dilute nitric acid to give its nitrate and hydrogen gas.

(iii) Hydrogen - Zinc will react with sulphuric acid to form zinc sulphate and release hydrogen gas.

(iv) Chlorine - The reaction of potassium permanganate with concentrated hydrochloric acid gives chlorine gas.

(v) Nitrogen dioxide - Sulfur reacts with nitric acid to produce Sulfuric acid, Nitrogen dioxide gas and water.

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