Name the gas liberated when potassium sulphite is treated with with dilute HCl
Answers
Answered by
1
Answer:
PSO3+HCL=PCL2+H2S04+H2
Answered by
0
Answer:
K2SO4 + 2HCl. = 2KCl + H2SO4
i think h2so4 fumes will be liberated
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