Question

Name the oxidation state of phosphorous in H₄P₂O₆ and H₄P₂O₇?

Answer 1

+4 and +5 respectively. check the images attached for reason

Answer 2

Answer:

So,Oxidation state of phosphorous in H₄P₂O₆ and H₄P₂O₇ is +4 and +5.

Explanation:

An oxidation state is number assigned to each element uin the given compound representing the electron loss to other element.

Let the oxidation state of phosphorous in H₄P₂O₆ is $x$

We know the oxidation state of hydrogen and oxygen which is 1 and -2 respectively.

So, $1\times4+2x+(-2\times6) = 0$

Solving for $x$ we get,

$x = 4$

Let the oxidation state of phosphorous in H₄P₂O₇ is $x$

So,$1\times4+2x+(-2\times7) = 0$

Solving for $x$ we get,

$x = 5$

So,Oxidation state of phosphorous in H₄P₂O₆ and H₄P₂O₇ is +4 and +5.