Question

Name the physical quatity which dimesnsional formula is M^-1L^3T^-2.​

Answer 1

Answer:

$\bf \color{fuchsia} {{\huge \Rightarrow}}Answer$

$\bf \color{fuchsia} {{\huge \Rightarrow}}Gravitational constant$

The gravitational constant, denoted by the letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's general theory of relativity.

Explanation:

Answer 2

Answer:

Gravitational constant (G).

Proof:

Just remember;

$\sf G= \dfrac{Fr^2}{Mm}$

Where:

• F is force [M L T⁻²]
• M and m are masses. [M]

• r is distance. Now, distance = Speed × Time ([M⁰ L¹ T⁻¹] and [M⁰ L⁰ T¹])

Therefore, substituting:

$\sf G= \dfrac{[M L T^{-2}] \times ([M^0 L^1 T^{-1}] \times [M^0 L^0 T^1])^2}{M^2}$

Solving this, we get:

$\sf G= \dfrac{L^3}{T^2M}$

$\sf G= M^{-1} L^3T^{-2}$

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