name the polygon whose sum of interior angle is 1440
Answers
Answered by
3
let the number of sides = n
we have
180(n-2)= 1440
n-2 = 8
n= 10
therefore the polygon has 10 sides aka decagon
we have
180(n-2)= 1440
n-2 = 8
n= 10
therefore the polygon has 10 sides aka decagon
Answered by
15
we know that sum of interior angle of a polygon=2(n-2)×90°
here sum of interior angles=1440°
according to the question,
(2n-4)×90=1440
or,180n-360=1440
or,180n=1440+360
or,180n=1800
or,n=1800/18
or,n=10
therefore,name of the polygon is decagon
exterior angle of decagon=360°/n
exterior angle of decagon=360°/10=36°
diagonals of decagon=n(n-3)/2
diagonals of decagon=10(10-3/2=10×7/2=70/2=35
Decagon is polygon who has 10 sides
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