Name the polynomial: 2m+3n−4n *
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Let (a−b) and (c−d) be two binomials. By using the distributive law of multiplication over subtraction twice, we can find their product as given below.
(a−b)×(c−d)=a×(c−d)−b×(c−d)=(a×c−a×d)−(b×c−b×d)
=ac−ad−bc+bd
∴(3m−4n)(2m−3n)
=3m×(2m−3n)−4n×(2m−3n)
=[(3m×2m)−(3m×3n)]−[(4n×2m)−(4n×3n)]
=(6m
2
−9mn−8mn+12n
2
)
=(6m
2
−17mn+12n
2
)
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