Question

Name the type of hybridization present in: [Co(NH3)6] 3+

Answer 1

Explanation:

Co3+ has 6 electrons in 3d orbital out of which four are unpaired. Strong ligands like ammonia can pair up these 4 unpaired electrons and free up two 3d orbitals. These 3d orbitals are involved in hybridisation along with one 4s and three 4p orbitals forming an inner orbital complex.

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Answer 2

Explanation:

[Co(NH3)6]3+ is an octahedral complex with metal center Co3+ having a configuration of [Ar]3d6. The six electrons on 3d orbital doubly fill the three suborbital. The electron pairs donated by ammine ligands (12 in total) are accommodated two each in the two suborbital of 3d, 4s and 4p (4px, 4py and 4pz). Therefore the hybridization involved is d2sp3.