Question

Name the type of quadrilateral formed by the points A(2,-1) , B(3,4) , C(-2,3) and D(-3,-2) in a plane.Also find the area of the quadrilateral so formed.

Answer 1

area of llgm ABCD=AD×AB
6×8=48

Answer 2

MARK ME AS THE BRAINLIEST!!

Answer:

AB = √(3-2)²+(4-(-1)²

=√1+25

AB = √26

BC = √(-2-3)²+(3-4)²

=√25+1

=√26

CD=√(-3+2)²+(-2-3)²

=√26

DA = √ (-3-2)²+(-2+1)²

=√25-1

=√26

therefore AB=BC=CD=DA

Therefore all the sides are equal

AC=√(-2-2)²+(3+1)²

=√16+16

=√32

BD=√(-3-3)²+(-2-4)²

=√36+36

=√72

AC is not equal to BD

Therefore the diagonals are not equal

The condition by these points are,

✓ All the sides are equal.

✓ Diagonals are not equal.

Therefore, it is a RHOMBUS

Area of a rhombus = 1/2 * (AC * BD)

=1/2 *(√32*√72)

Therefore , Area of the given RHOMBUS = 24 sq. units

Hope it helps!!