Question

name the type of quadrilateral formed by the vertices (-2,0),(3,2),(2,-1)and (-3,-3). give reasons​

Answer 1

Answer:

it is square because the distance of each side is equal.

Answer 2

It is a parallelogram

Step-by-step explanation:

using the distance formula

distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

then

AB =$\sqrt{(3+2)^2+(2-0)^2}$

AB = $\sqrt{29}$

BC =  $\sqrt{(2-3)^2+(-1-2)^2}$

BC = $\sqrt{10}$

CD = $\sqrt{(-3-2)^2+(-3+1)^2}$

CD = $\sqrt{29}$

DA = $\sqrt{(-3+2)^2+(-3+0)^2}$

DA = $\sqrt{10}$

AC = $\sqrt{(2+2)^2+(-1+0)^2}$

AC = $\sqrt{15}$

BD = $\sqrt{(-3-3)^2+(-3+2)^2}$

BD = $\sqrt{61}$

Since , the diagonals are not equal but

opposite sides are equal

hence ,

it is a parallelogram

#Learn more:

The area of the quadrilateral formed by vertices (2,-1),(4,3),(-1,2) and (-3,2)

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