Question

Namrata brought two dresses for ₹ 1200. She sold one of them at a profit of 8% and another at loss of 6%. Selling price of both dresses is same find the cost price of each dress

Answer 1

Answer:

Let the CP be x and 1200-x

Xx108/loo=(1200-x) 94/loo

Xx108 = (1200-x) 94

108x=112800-94x

202X=112800

x=112800/200=564

1200-x = 1200-564=636

costprice=Rs 564 and Rs 636

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Answer 2

Cost price of first dress is Rs. 558.42 and the cost price of second dress is Rs. 641.58

Step-by-step explanation:

Let the cost price of first dress be 'x'.

Let the cost price of second dress be '1200-x'.

Profit on first dress = 8%

Loss on second dress = 6%

According to question, selling price of both dresses is same, so we get that

$\dfrac{100+8}{100}\times x=\dfrac{100-6}{100}\times (1200-x)\\\\\dfrac{108}{100}x=\dfrac{94}{100}(1200-x)\\\\1.08x=0.94(1200-x)\\\\1.08x=1128-0.94x\\1.08x+0.94x=1128\\\\2.02x=1128\\\\x=\dfrac{1128}{2.02}\\\\x=558.42$

Hence, Cost price of first dress is Rs. 558.42 and the cost price of second dress is Rs. 1200 - Rs. 558.42 =Rs. 641.58

# learn more:

Mona got two dresses for 1648. She sold one at a profit of 15% and the other at a loss of 9% . If she got the same amount for each dress then find the cost price of each of the dresses.

https://brainly.in/question/5079150