Chemistry, asked by sansthita09, 10 months ago

NaNO3 + H2SO4(conc.) + Cu ---> NaHSO4 + Cu(NO3)2 + H2O + NO2

...please balance this equation properly please... ​

Answers

Answered by DevanshVats
1

Answer:

NaNO3+H2SO4 +Cu → NaHSO4 + Cu(NO3)2 + H2O + NO2

3Cu + 8NaNO3 + 4H2SO4

3Cu(NO3)2 + 4H2O + 2NO

+ 4Na2SO4

LHS,

Na=.8 N= 8 O=40 H= 8 S=4 Cu= 3

RHS,

Na=8 N=8 O=4p H= 8 S=4 Cu= 3

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Answered by Siddharta7
0

Explanation:

Given:

NaNO₃ + H₂SO₄ + CU  ---> NaHSO₄ + Cu(NO₃)₂ + H₂O + NO₂

Balancing the Equation:

Cu + 4NaNO₃ + 4H₂SO₄  ---> 4NaHSO₄ + CU(NO₃)₂ + 2H₂O + 2NO₂

Hope it helps!

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