Question

NAOH+excess sulphur boil​

Answer 1

Answer:

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Explanation:

Sulfur reacts with sodium hydroxide in the following way:

3S+6NaOH⟶2Na

2

S+Na

2

SO

3

+3H

2

O

It is a disproportionation reaction: sulfur's oxidation changes from zero to -2 in sodium sulfide and from zero to +4 in sodium sulfite.

But how to remember the products of this reaction? By rote memorization?

The preparation of sodium sulfide is apparent. Is there a way to understand why sodium sulfite forms? We have the hydroxide ion, and it somehow reacts with sulfur to yield the SO

3

2− ion - but how?

Answer 2

Answer:

Sulfur reacts with sodium hydroxide in the following way:

3S+6NaOH⟶2Na

2

S+Na

2

SO

3

+3H

2

O

It is a disproportionation reaction: sulfur's oxidation changes from zero to -2 in sodium sulfide and from zero to +4 in sodium sulfite.

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