Question

narayan murthy walking at a speed of 20km/hr reaches his college 10 min late next time he increases his speed by 5km/hr but finds again 4 min late then what is distance of his college from his house

Answer 1

Hi..

By increasing his speed by 25%, he will reduce his time by 20%. (This corresponds to a 6 minutes drop in his time for travel - since he goes from being 10 minutes late to only 4 minutes late). Hence, his time originally must have been 30 minutes. Hence, the required distance is 20 kmph x 0.5 hours = 10 km...

Hope this helps u

Answer 2

heya dear your answer is here
______$______

actual time =t

distance at speed1=distance at speed2

20*(t+1/6)=25*(t+1/15)
4t+4/6=5t+1/3
t=2/3-1/3
t=1/3hour
t=20mins

so distance=20×(1/3+1/6) =20*1/2 =10km