Question

nature of roots of quadratic equation 2x2-4x+3=0

Answer 1

given equation, 2x²-4x+3=0
=>x=4±√16-24/4=> the roots of the equation are imaginary.
so it has no real or distinct roots.

Answer 2

Answer:

The nature of quadratic equation is no real roots.    

Step-by-step explanation:

Given : Quadratic equation $2x^2-4x+3=0$

To find : Nature of the roots of quadratic equation?

Solution :

To determine the nature we find discriminant, $D=b^2-4ac$

1) If D<0, no real roots.

2) If D=0, two equal real roots.

3) If D>0, two distinct real roots.

Now, we find discriminant.

$2x^2-4x+3=0$

Here, a=2,b=-4,c=3

$D=(-4)^2-4(2)(3)$

$D=16-24$

$D=-8$

So, D<0 there is no real roots.

Therefore, The nature of quadratic equation is no real roots.