Math, asked by GothaalaSheoran9764, 8 months ago

nature of roots of x^-9x+20=0

Answers

Answered by monu26202

1

Answer:

Real and distinct.

Step-by-step explanation:

d=b^-4ac

= (-9)^-4×1×20

= 81-80

= 1

i.e., d>0

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