Nature of roots:: (x-2a) (x-2b) = 4ab
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Answered by
63
given equation is
(x-2a)(x-2b)=4ab
x²-2bx-2ax-4ab=0
x²+[-2(a+b)]x+(-4ab)=0
here A=0;B=-2(a+b);C=-4ab
determinent=B²-4AC
=[-2(a+b)]²-4(0)(-4ab)
=4(a+b)²-0
=[2(a+b)]²
we know that any x€R;x²>0
so [2(a+b)]²>0
determinent>0
so,roots of given equation are positive integers.
.
hope it'll help
mark it as brainliest
(x-2a)(x-2b)=4ab
x²-2bx-2ax-4ab=0
x²+[-2(a+b)]x+(-4ab)=0
here A=0;B=-2(a+b);C=-4ab
determinent=B²-4AC
=[-2(a+b)]²-4(0)(-4ab)
=4(a+b)²-0
=[2(a+b)]²
we know that any x€R;x²>0
so [2(a+b)]²>0
determinent>0
so,roots of given equation are positive integers.
.
hope it'll help
mark it as brainliest
Answered by
29
hello dude refer to pic above...
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