nC10=nC12 . find 23Cn
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n!/10!(n-10)!=n!/12!(n-12)!
1/10!(n-10)×(n-11)!×(n-12)!=1/12×11×10!×(n-12)!
1/(n-10)×(n-11)= 1/12×11
12= n^2--11n-10n+110
n^2-21n+98=0
after factorization....
(n-14). (n-7). =0
n=14,7
after put the value of n in....
23!/n!(23-n)!....1. put n=14...
.................. put n=7after solving you get value of 23cn....
1/10!(n-10)×(n-11)!×(n-12)!=1/12×11×10!×(n-12)!
1/(n-10)×(n-11)= 1/12×11
12= n^2--11n-10n+110
n^2-21n+98=0
after factorization....
(n-14). (n-7). =0
n=14,7
after put the value of n in....
23!/n!(23-n)!....1. put n=14...
.................. put n=7after solving you get value of 23cn....
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hope it helps....... :)
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