Math, asked by chandik, 1 year ago

ncert 10th maths exercise 3.5 first question

Answers

Answered by tanu66
7
and the following 4 answer is here .

x/ 45-21 = y/-21+15. = 1/ -3+9

x/24. = y/ -6. = 1/-6

Now compare the equations

x/24=1/-6. , y /-6 =1/-6

x(-6) = 1(24) , y (-6)= 1(-6)

-6x = 24. , -6y =-6

x=24/-6
= 4 , y = -6/-6 = 1.......
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tanu66: hope it helps... ☺
Answered by Anonymous
3
Q-1 ) (a) x-3y-3=0
3x-9y-2=0
the given system of equation is
x-3y-3=0
and 3x-9y-2=0
these are of the form a1x+b1y+c1=0
a2x+b2y+c2=0
where a1 = 1, b1 = -3, c2 = -3 and a2 = 3, b2 = -9,c2 = 2
we have, a1 / a2 = 1 / 3,b1 / b2 = -3 / -9=1 / 3 and c2=-3 / -2 =3 / 2
clearly, a1 / a2 us equal to b1 / b2 is not equal to c1 / c2
so,the given system of equations has no solution
it is inconsistent.
Hope it will help you.
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