NCERT10 CLASS MATHS EX6.2 QUESTION5
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5. In figure, DE OQ and DF OR. Show that EF QR.
In PQO, DE OQ
[Basic Proportionality theorem] ……….(i)
And in POR, DF OR
[Basic Proportionality theorem] ……….(ii)
From eq. (i) and (ii), we have
EF|| QR [By the converse of BPT]
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