Question

Ncharge droplets coalesce together to form a bigger charge drop (spherical). The ratio of
electric potential at the surface of bigger drop and that at the surface of single charge droplet is​

Answer 1

Answer ⇒ $V/v = n^{\frac{2}{3} }$

Explanation ⇒

Let the potential of the bigger drop be V and that of each n smaller drop be v.

Volume of bigger sphere = n × Volume of smaller sphere.

4/3 × πR³ = n × 4/3 × πr³

R = r × ∛n

Potential of bigger drop = V = kQ/R

Potential of smaller drop = v = kq/r

Now, Q = nq [Since charge will also gets add up as it is an additive quantity.]

∴ V = knq/r × ∛n and v = kq/r

∴ V/v = ∛n

∴  $V/v = n^{\frac{2}{3} }$

Hope it helps.