Question

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23. A 7 kg object is subjected to two
forces E - (201 + 30 j) and
E = (8+5 j) N. The magnitude of
resulting acceleration in m/s will
be
(a) 6 (b) 7 (c) 1 (d) 5.3​

Answer 1

Answer:

• F = F1 + F2

• F = (20i˄ + 30j˄) + (8i˄ – 5j^)

• F = 28i˄ + 25j˄

• |F| = √(282 + 252) = √(1409) = 37.53 N

• As F = m × a

• a = (F / m)

• = {(37.53) / 7

• a = 5.36 = 5 m/s2

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