ne braking distance of a vehicle is directly proportional to the square of its speed. When the speed of the vehicle is b m/s, its braking distance is d m. If the speed of the vehicle is increased by 200%. find the percentage increase in its braking distance 7
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We can assign variables as:
= original breaking distance
= original speed of the vehicle
= increased breaking distance
= increased speed of the vehicle
We can look at it this way, originally it was like this:
Now, if we increase the speed to b’ which 200% more than b, we will have
Obtaining the difference between d and d’, we have
in terms of d
Adding d on both sides of the equation,
Which means the original breaking distance is increased by 800%. This is similar to the phrase “the speed of the vehicle is increased by 200%” which translates to “b + 2b”.
Hope this helps.
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