Nearest two number of 10000 which is exactly divisible by2,3,4,5,6 and7
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Step 1: Take the LCM of given numbers. LCM of (1, 2, 3, 4, 5, 6 and 7 ) = 420
Step 2: Divide 10000 by 420, in which the value comes nearest to 10000 When 420 is divided by 23, it gives a remainder of 340
Step 3: Subtract 340 from 10000 = 10000 - 340 = 9660 Therefore, 9660 is the first number which is nearest to 10000 and divisible by 1, 2, 3, 4, 5, 6 and 7. Step 4: Multiply 420 by 24 to get the second nearest number 420 * 24 = 10080 Therefore, the two numbers are 9660 and 10080
Step 2: Divide 10000 by 420, in which the value comes nearest to 10000 When 420 is divided by 23, it gives a remainder of 340
Step 3: Subtract 340 from 10000 = 10000 - 340 = 9660 Therefore, 9660 is the first number which is nearest to 10000 and divisible by 1, 2, 3, 4, 5, 6 and 7. Step 4: Multiply 420 by 24 to get the second nearest number 420 * 24 = 10080 Therefore, the two numbers are 9660 and 10080
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