need a proper answer for this
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____________
Here, we can say that
Sum of roots = - b/a
Product of roots = c/a
Suppose the roots are
Alpha = A
Beta = B.
So,
1/A^2 + 1/B^2
= [ (A + B)^2 - 2AB ] / (AB)^2
= (b^2/a^2 - 2c/a) / (c^2/a^2)
= (b^2 - 2ac)/a^2 * a^2/c^2
= (b^2 - 2ac) / c^2
_____________
Thanks..
Answered by
0
Step-by-step explanation:
Here, we can say that
Sum of roots = - b/a
Product of roots = c/a
Suppose the roots are
Alpha = A
Beta = B.
So,
1/A^2 + 1/B^2
= [ (A + B)^2 - 2AB ] / (AB)^2
= (b^2/a^2 - 2c/a) / (c^2/a^2)
= (b^2 - 2ac)/a^2 * a^2/c^2
= (b^2 - 2ac) / c^2.
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