Question

NEED ANSWER OF
$\sqrt[ 9]{ \infty }$
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Answer 1

THEORY OF CALCULUS -

$\sqrt[9]{ \infty } = { \infty }^{ \frac{1}{9} }$
Literally INFINITY isn't any number , it's an concept about number series going to be uncountable in state to manipulate any mathematical operations like addition , subtraction ...

INFINITY can be deviced for Integers , Rationals , Terminating and Non terminating decimal expansions , everything ,

If the same happens with negative integers it's minus INFINITY ,
now coming to your question,
as the expression yields that

INFINITY raised to 1/9

or INFINITY raised to any constant is also an infinite concept ,
it doesn't matter whatever you're keeping on its exponential function , it'll always remain INFINITY according to theory ,


- Lycon Trix

Answer 2

Hey friend!!

Here's ur answer...

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$\sqrt[9]{ \infty } = { \infty }^{ \frac{1}{9} } \\ so \: it \: can \: also \: be \: written \: as \: - \: \: \: \: \: \: \\ \\ (1 + 1 + 1 + ..... {)}^{ \frac{1}{9} } \\ = (1 + 2 + 3 + 4 + ..... {)}^{ \frac{1}{9} } \\ \\ According \: to \: the \: theory \: of \: Srinivasa \: Ramanujan \: sum \: of \: first \: n \: infinite \: numbers \: \\ = \frac{-1}{12} \\ \\ so \: \sqrt[9]{ \infty } = ( \frac{-1}{12} {)}^{ \frac{1}{9} } It's value is negative. Hope it may help you...$
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Hope it is correct =_=

Thank you :) :))