Question

Need answer with deep explanation???​

Answer 1

Required Answer:

Parallel line to 3x + 4y = 7 is of the

form 3x + 4y= 3x1 + 4y1.

Let (x1 , y1) be (1,2)

→ 3x + 4y = 3(1)+4(2)

3x + 4y = 11

Perpendicular line to 3x + 4y = 7 is of the form

4x - 3y = 4x1 - 3y1

Here (x1, y1) = (1,2)

→ 4x - 3y = 4(1)-3(2)

4x - 3y = -2

Therefore, The parallel and perpendicular lines are respectively.

3x + 4y = 1

4x - 3y = -2

Thank you for asking such an useful Question Mate.