need explanation pls
A crane machine is used to lift cement slabs of weight w at Delhi metro site. Machine have to lift the slabs from rest and have to put them on the elevated platform at a height ‘h’. If the maximum tension that the cable of crane machine can tolerate is nw (n > 1), then minimum time in which ascent can be done by the machine is (Tmin = 0)
ANS: (2nh/(n-1)g)^1/2
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Answer:
Given that,
The force acting on the crane, F = 5000 N
It is lifted upward to a height of 20 meters, h = 20 m
To find,
The work done by the crane
Solution,
The work done by an object due to height is called its potential energy. It is given by :
E=F\times hE=F×h
E=5000\ N\times 20\ mE=5000 N×20 m
E=10^5\ JE=105 J
So, the work done by the crane is 10^5\ J105 J .
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