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The value of
tan60-tan30/1+tan60×tan30
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Hey there,
Given tan60°-tan30°/1+tan60°-tan30°
It is in the form of (tanA - tanB)/(1 - tanA tanB) which is equal to tan(A - B)
Hence tan60°-tan30°/1+tan60°-tan30° = tan(60° − 30°)
= tan(30°)
=1/√3
Hope this helps!
Given tan60°-tan30°/1+tan60°-tan30°
It is in the form of (tanA - tanB)/(1 - tanA tanB) which is equal to tan(A - B)
Hence tan60°-tan30°/1+tan60°-tan30° = tan(60° − 30°)
= tan(30°)
=1/√3
Hope this helps!
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