Need help.........anyone genius out there to solve 52?
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hey mate
here is your answer
ang cbe= Ang cae
in ∆cae
Ang ace=180-(90+50)
=180-140
=40
therefore Ang ced=40
here is your answer
ang cbe= Ang cae
in ∆cae
Ang ace=180-(90+50)
=180-140
=40
therefore Ang ced=40
rohitmaddaly02:
you
jamshedpur (jharkhand)
ohh nice
yuo
you studied
nope not at all
nice
I did so I'm happy!
good
ok gtg bye
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