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Given:-
→ Mass of the body = 500kg
→ Initial speed of the body = 5m/s
→ Final speed of the ball = 3m/s
To find:-
→ Change in Kinetic energy of the body
Solution:-
Let the initial speed of the body be v₁ and the final speed of the body be v₂.
• K.E. = 1/2mv²
Thus, change in K.E. will be:-
= 1/2mv₂² - 1/2mv₁²
= m/2( v₂² - v₁² )
= 500/2[ (3)² - (5)² ]
= 250[ 9 - 25 ]
= 250[ -16 ]
= - 4000 J
[ Here, -ve sign represents that K.E. gets reduced by 4000 J ]
Thus, the decrease in kinetic energy of the body is 4000 J.
Some Extra Information:-
• Kinetic energy is the energy possessed by a body because of it's motion.
• K.E. = 1/2mv²
This expression shows that kinetic energy of a body depends on two factors.
(a) Mass [K.E ∝ m]
(b) Velocity [K.E. ∝ v² ]
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