Question

need help please help me​

Answer 1

Answer:

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Circumference of circle=

$2\pi \: r$

Inner circumference=176m

So,

$2 \times \frac{22}{7} \times r = 176m$

$r = 176 \times \frac{7}{44}$

$r = 28m$

Inner Radius of track (r)=28m

The track is 7m in width

Outer Radius (R)=28+7=35m

Area of track=Outer Area- Inner Area

$= \pi \: R {}^{2} - \pi \: r {}^{2}$

$= \frac{22}{7} (35 {}^{2} - 28 {}^{2} )$

$= 1386m {}^{2}$

Area of track =1386m²

Outer circumference=

$2\pi \: r$

$= 2 \times \frac{22}{7} \times 35$

$= 220m$

Cost of fencing 1m=Rs. 12

Cost of fencing 220m=Rs12×220

Cost of fencing=Rs2640