Question

need help please step by step

Answer 1

Step-by-step explanation:

angle APB = 90 { angle in a semicircle }

so angle PBA + angle PAB + angle APB = 180

angle PBA = 180 -(90 + 55)

= 180 - 145

angle PBA = 35

in given figure, ABQP is a cyclic quadrilateral

so angle BAP + angle BQP = 180 { opposite side of a cyclic quadrilateral}

angle BQP = 180 - 55

angle BQP = 125

so angle BPQ + angle BQP + angle PBQ = 180

angle BPQ = 180 - ( 125 + 25 )

angle BPQ = 180 - 150

angle BPQ = 30

angle ARB = 90 { angle in a semicircle }

so angle BAR + angle ABR + angle ARB = 180

angle BAR = 180 - ( 50 + 90 )

angle BAR = 180 - 140

angle BAR = 40

Hence

angle PBA = 35

angle BPQ = 30

angle BAR = 40

please mark this as brain least answer.......