Question

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q. if x-1/x=3 then find x^3-1/x^3



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Answer 1

Given:

= > x - (1/x) = 3.

On cubing both sides, we get

= > (x - 1/x)^3 = (3)^3

$= \ \textgreater \ x^3 - \frac{1}{x^3} - 3 * x * \frac{1}{x} (x - \frac{1}{x} ) = 27$

$= \ \textgreater \ x^3 - \frac{1}{x^3} - 3(3) = 27$

$= \ \textgreater \ x^3 - \frac{1}{x^3} - 9 = 27$

$= \ \textgreater \ x^3 - \frac{1}{x^3} = 27 + 9$

$= \ \textgreater \ x^3 - \frac{1}{x^3} = 36$



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