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THE SUM OF 8TIMES OF A NUMBER ANE 9TIMES OF ANOTHER NUMBER IS 186.THE SUM OF 9 TIMES OF THE FIRST NUMBER AND 8TIMES OF SECOND NUMBER IS 188.WHAT ARE THE TWO NUMBERS
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sorry weak in maths dear friend
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first no. = x
second no. = y
8x + 9y = 186
9x + 8y = 188
Solve 8x + 9y = 186 for x
8x = 186 - 9y
x = 186 - 9y / 8 = 93/4 - 9y/8
Substitute 93/4 - 9y/8 for x in 9x + 8y = 188
9*(93/4 - 9y/8) + 8y = 188
837/4 - 81y/8 + 8y = 188
(-81y + 64y)/8 = 188 - 837/4
-17y/8 = -85/4
y = -85/4 ÷ -17/8
y = -85/4 * -8/17 = 170/17 = 10
y = 10
substitute y = 10 in 8x + 9y = 186
8x + 90 = 186
8x = 186 - 90 = 96
x = 96/8 = 12
x = 12
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