Question

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Answer 1

||✪✪ QUESTION ✪✪||

Given in image ..

|| ✰✰ ANSWER ✰✰ ||

Let us assume That :-

→ f(x) = √x

→ g(x) = √(x²+x)

→ h(x) = (1/x)

As we to composite into Three Functions ..

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First Lets Solve by Putting value of f(x) into g(x) :-

→ g(f(x)) = √[f(x))² + f(x)]

→ g(f(x)) = √[ (√x)² + (√x) ]

→ g(f(x)) =✓[ x + (√x) ] { As (√a)² = a. }

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Now, putting g(f(x)) in h(x) , we get :-

→ h(g(f(x))) = 1/g(f(x))

→ h(g(f(x))) = 1/✓[ x + (√x) ]

So,

→ F(x) = 1/✓[ x + (√x) ]

✪✪ Hence Proved ✪✪

Answer 2

Step-by-step explanation:

$\huge\underline\yellow{\sf Answer :-}$

$\large\implies{\sf }$ Check the attached picture