Math, asked by Marshmello9, 1 year ago

Need solution..................

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Answered by siddhartharao77
7
 Given  :  \lim_{2}  \frac{x^3 - 8}{x^4 - 16}

 \lim_{2}  \frac{(x-2)(x^2 + 2x + 4)}{(x + 2)(x - 2)(x^2 + 4)}

 \lim_{2}  \frac{x^2+2x+4}{(x+2)(x^2+4)}

 \frac{2^2 + 2(2) + 4}{(2 + 2) * (2^2 + 4)}

 \frac{4 + 4 + 4}{(4)(4 + 4) }

 \frac{12}{32}

 \frac{3}{8}



Hope this helps!
Answered by anuj
11
We can  apply L'Hospital Rule When the indeterminate expression  is the form of  0/0 or ∞/∞

[To find the limits of other indeterminate forms we try to convert each form to 
 0/0 or ∞/∞ and apply L'Hospital rule]

See the IMAGE: FOR SOLUTION

THE ANSWER IS 3/8.

We  differentiate the NUMERATOR And DENOMINATOR separately 



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