please answer the questions quickly
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4th is correct option
on cross multiplying we get x^2 - bx = a^2 -ab
on rearranging x^2 - a^2 = bx - ab
(x-a) (x+a) = b(x-a)
(x-a)(x+a) - b(x-a) =0
(x-a) [x + a -b] = 0
thus x = a or x = b-a
on cross multiplying we get x^2 - bx = a^2 -ab
on rearranging x^2 - a^2 = bx - ab
(x-a) (x+a) = b(x-a)
(x-a)(x+a) - b(x-a) =0
(x-a) [x + a -b] = 0
thus x = a or x = b-a
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