need solution of the ques
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x2 + y2 = t + 1/t
Squaring both sides
x4 + y4 + 2x2y2 = t2 + 1/t2 + 2
2x2y2 = 2 { since x4 + y4 = t2 + 1/t2}
x2y2 = 1
Differentiate both sides wrt x
2x.y2 + x2.2y.dy/dx = 0
dy/xx = -2x.y2/x2.2y
dy/dx = - y/x
Squaring both sides
x4 + y4 + 2x2y2 = t2 + 1/t2 + 2
2x2y2 = 2 { since x4 + y4 = t2 + 1/t2}
x2y2 = 1
Differentiate both sides wrt x
2x.y2 + x2.2y.dy/dx = 0
dy/xx = -2x.y2/x2.2y
dy/dx = - y/x
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