Physics, asked by Anonymous, 10 months ago

needed with clear explanation​

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Answered by AbdJr10
1

Answer:

final \: amount = initial( { \frac{1}{2} )}^{ \frac{t1}{t \: half} }  \\  \frac{2}{3}  =  { (\frac{1}{2}) }^{ \frac{t1}{20} } ......eq1 \\  \frac{1}{3}  =  { (\frac{1}{2}) }^{ \frac{t2}{20} } .....eq2 \\ devide \: both \: the \: eq \\ we \: get... \\  { \frac{1}{2} }^{1}  =  { \frac{1}{2} }^{ \frac{t1 - t2}{20} }  \\ so \: base \: are \: same \:  \\  1 =  \frac{t1 - t2}{20}   \\ t1 - t2 = 20

hope the answer will help you

Answered by anupamdwivedi1971
3

(B) 20min

Hope that help .

Best of luck for NEET!!!☺☺

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