Question

neera saves rs. 1600 in the first year , rs. 2100 in the second year and rs. 2600 in thr third . in hw many years will she save rs,. 38500

Answer 1

Answer:

10 years.

Step-by-step explanation:

Neera savings:

First year =Rs.1600

Second year =Rs.2100

Third year =Rs.. 2600

Sequence : 1600,2100,2600 ...

So, a = first term = 1600

Common difference = d = 2100-1600=2600-2100=500

So,sum of first n terms = $S_n=\frac{n}{2}(2a+(n-1)d)$

So, to find . in how many years will she save rs,. 38500

$38500=\frac{n}{2}(2(1600)+(n-1)500)$

$77000=2700n+500n^2$

$n=\frac{-77}{5} ,10$

Hence she will save Rs.38500 in 10 years.

Answer 2

Step-by-step explanation:

i hope it will be help you