Physics, asked by alpana37589, 11 months ago

Neeta travelled the first 3 hours of her hours of her journey at 60 km/h. She travelled the next 5 hours at 35 km/h. What was the total length of her journey? Now calculate what her average speed was.​

Answers

Answered by Divy0prakash
4

This is your answer hope it help you please mark as brainlist

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Answered by Cynefin
57

 \large{ \bold{ \dag{ \red{ \underline{ \underline{Question...}}}}}}

Neeta travelled the first 3 hours of her hours of her journey at 60 km/h. She travelled the next 5 hours at 35 km/h. What was the total length of her journey? Now calculate What her average speed was?

 \large{ \bold{ \dag{ \green{ \underline{ \underline{Answer...}}}}}}

  • Total distance= 355km
  • Avg speed= 44.375 km/hr

 \large{ \bold{ \dag{ \red{ \underline{ \underline{Solution...}}}}}}

 \sf{ \bold{ \star{ \orange{ \underline{ \underline{given...}}}}}}

  • Three hours with speed 60 km/hr
  • five hours with speed 35 km/hr

 \sf{ \bold{ \star{ \orange{ \underline{ \underline{to \: find...}}}}}}

  • Total length of journey
  • Average speed.

 \large{ \sf{ \bold{ \pink{ \underline{according \: to \: question}}}}}

  \large{ \sf{ \underline{1st \: part}}} \\ \large{ \sf{ \implies{speed \: of \: neeta = 60 \: km \: h {}^{ - 1} }}} \\  \\  \large{ \sf{ \implies{time \: taken = 3 \: hours}}} \\  \\  \large{ \sf{ \boxed{ \green{speed =  \frac{distane}{time} }}}} \\  \red{ \large{ \sf{ \implies{then \: distance = speed \times time}}}} \\  \\  \large{ \sf{ \implies{distance = 60 \times 3 = 180 \: km}}} \\  \\  \large{ \sf{ \underline{2nd \: part}}} \\  \\  \large{ \sf{ \implies{speed \: of \: neeta = 35km \: h {}^{ - 1} }}} \\  \\  \large{ \sf{ \implies{time \: taken = 5 \: hours}}} \\  \\  \large{ \sf{ \implies{distance = 35 \times 5 \: km = 175 \: km}}} \\  \\  \large{  \leadsto{ \green{ \bold{total \: distance = 180 + 175 = 355 \: km}}}} \\  \\    \large{ \sf{we \: know...}}\\ \large{ \sf{ \boxed{ \red{avg. \: speed \:  =  \frac{total \: distance}{total \: time \: taken} }}}} \\  \\  \large{ \sf{ \implies{total \: distance = 355km}}} \\  \\  \large{ \sf{ \implies{total \: time \: taken = 3 + 5 = 8 \: hours}}} \\  \\  \large{ \leadsto{ \bold{ \green{avg. \: speed =  \frac{355 \: km}{8 \: hrs}  = 44.375 \: km \: hr {}^{ - 1} }}}}

   \large{ \bold{ \pink{required \: answer \: is \: 355km \: and \: 44.375km \: h {}^{ - 1} }}}

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