Psychology, asked by sidnaaz, 3 months ago

Nehru Yuva Kendra on 7, Bahadur Shah Zafar Marg, New Delhi, is an organisation catering to the cultural needs of the youth. Write a letter to the Director, enquiring about the short-term courses/classes scheduled for the summer vacations. You are particularly interested in drama and martial arts programmes. Sign as Raghuvir Singh, 50, Daryaganj, Delhi.

Answers

Answered by XxmiragexX

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Daryaganj

Delhi

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4 December, 20XX

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To,

The Director

Nehru Yuva Kendra

7, Bahadur Shah Zafar Marg

Delhi

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Sub : Enquiring about short - term courses.

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Respected sir,

Through this letter, I wanted to enquire about Short - Term courses and classes which were scheduled in summer vacations of this year. Sir, two months ago you announced that your organization will be offering vocational course classes to the youths. But sir we have got no information about it yet. Sir I am particularly interested in drama and martial arts program.

Sir can you please announce the dates and beginning of these classes ? Sir please provide me the details of fees of those courses, time taken and the days for courses with time tables. Sir all these will help us prepare our chores accordingly.

Sir all these courses shall help us in moulding our future more better. Sir I wanted to know the venue of these courses and hoe many participants in maximum can participate in each course from each school and of each age category.

Kindly provide me details for all these.

Hoping for your positive response on this.

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Thanking you

Yours sincerely

Raghuvir Singh

Answered by kapilchavhan223

Answer:

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Width of rectangle is 25 cm.

Step-by-step explanation:

Given :-

A wire bend in form of square of side 30 cm.

Then wire is again bend in form of rectangle of length 35 cm.

To find :-

Width of the rectangle.

Solution :-

Here, Concept is : If we are bending wire in form of square than again bending it in rectangle. Than, perimeter of square will equal to perimeter of rectangle because we are not increasing length of wire by one measure we are bending it in square and rectangular shape.

So,

Perimeter of square = 4 × side

⟶ Perimeter = 4 × 30

⟶ Perimeter = 120

Thus,

Perimeter of square is 120 cm.

According to concept, Perimeter of square and perimeter of rectangle are equal.

So, Perimeter of rectangle is 120 cm.

Let, Breadth or width or rectangle be x cm.

We know,

Perimeter of rectangle = 2(Length + Breadth)

⟶ 120 = 2×(35 + x)